Quote:
Originally Posted by Davross
Im not sure what you mean by the math aspect. The double winks are counted as 2 winks (hence the X *2). Could you clarify pls?

That bit's fine, it's the probability angle Marz is on about.
If the mongo's were 21% a piece, you'd get a chance of
[1(0.79 * 0.79)] = 37.59% that at least one mongo will wink.
I make the % chance for each to be roughly ~23.84% given your numbers.
If that's correct, then that leaves a 5.68% chance that both will wink.
*** Probably best that someone checks this for me, tad rusty on the ol' 'bilities.